Which of the following is a true statement?

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All the carbon in $H_{2} C = C - H - C = C - H - C = {CH}_{2}$

are in $s p^{2}$ hybridization.

$In C_{2} H_{2} (CN)_{2} there are six ' σ' bonds.$

$In diamond, ' C' is in s p^{2} hybridization$

$In C_{3} O_{2} all the carbons are in s p$ hybridization

answer is D.

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Detailed Solution

In Carbon suboxide all, the carbons are in sp hybridization is a true statement.

A sigma bond and a pi-bond are present in every double bond. The result is that each carbon atom will have two sigmas and two bonds at the same time. — Due to the two sigma and two bonds that each carbon bond in tricarbon dioxide possesses, the hybridization of carbon will be sp.

Hence, option D is correct.

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