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Q.

Which of the following is correct order for solubility in water?

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a

${NaClO}_{4} < {KClO}_{4}$

b

All of these

c

${MgSO}_{4} < {SrSO}_{4}$

d

${NaBF}_{4} > NaF$

answer is B.

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Detailed Solution

Because small fluoride ions have a larger hydration energy than big ${BF}_{4}^{-}$ ions. ${NaBF}_{4}$ is more soluble than NaF.

${NaBF}_{4} > NaF$

Correct option is B.

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