Which of the following is free radical addition reaction

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${CH}_{3} - {CH}_{3} + C l_{2} \overset{hv}{\to} {CH}_{3} - {CH}_{2} - Cl$

${CH}_{3} - CH = {CH}_{2} + HBr \overset{Peroxide}{\to} {CH}_{3} - {CH}_{2} - {CH}_{2} Br$

${CH}_{3} - CHO + HCN \to {CH}_{3} C H (OH) CN$

${CH}_{3} - CH = {CH}_{2} + HBr \to {CH}_{3} - CH (Br) - {CH}_{3}$

answer is D.

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Detailed Solution

Hydrogen Halides like HBr usually react with alkenes using an electrophilic addition mechanism. However, in the presence of organic peroxides, HBr adds to the carbon across the double bond which carries a lesser number of hydrogen atoms through free radical addition. This is called Anti-Markownikoff's rule.

This is called the peroxide effect or Anti-Markovnikovs rule.

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