Which of the following is incorrect about de Brogile relationship? 

de-Broglie suggested that radiation has both wave and particle character.

$\mathrm{\lambda }=\frac{\mathrm{h}}{\mathrm{mv}}=\frac{\mathrm{h}}{\mathrm{p}}$

So, expression present in option-1 and option-2 are correct.

$$\begin{gathered} \mathrm{\lambda }=\frac{\mathrm{h}}{\mathrm{mv}}\times \frac{\mathrm{v}}{\mathrm{v}}=\frac{\mathrm{hv}}{{\mathrm{mv}}^2} \\ {\mathrm{mv}}^2=\frac{\mathrm{hv}}{\mathrm{\lambda }}...\left(1\right) \\ {\mathrm{E}}_{\mathrm{Kinetic}}=\frac{1}{2} {\mathrm{mv}}^2=\frac{1}{2}\frac{\mathrm{hv}}{\mathrm{\lambda }} (\mathrm{from} 1) \end{gathered}$$

So, expression present in option-3 is also correct.