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Q.

Which of the following is ionic ?

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a

PbF4

b

SnCl4

c

CF4

d

SiF4

answer is A.

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Detailed Solution

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Among the options given, (a) PbF4 is expected to be primarily an ionic compound based on Fajan's rule.

Lead (Pb) has a relatively large atomic radius, and fluorine (F) has a small atomic radius. The cation Pb2+ is large compared to the anion F-. Moreover, the high charge on the Pb2+ ion (compared to the charge on other cations such as Sn2+) also increases the ionic character of the Pb-F bond.

On the other hand, SnCl4, CF4, and SiF4 are covalent compounds because the bond between the two atoms in each molecule is primarily covalent, and they do not have large enough differences in electronegativity to form ionic bonds.

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