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Which of the following is not correct ?

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$large pH, = ,frac{1}{{log [{H^ + }]}}$

$pH, = ,log (frac{1}{{{H^ + }}})$

$[{H^ + }], = ,{10^{ - pH}}$

$pH, = , - log [{H^ + }]$

answer is A.

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Detailed Solution

$P^H=-log[H^+]=log[H^+]^{-1}=logfrac{1}{[H^+]}$

$Also, [H^+]=10^{-P^H}Rightarrow P^H=-log{[H^+]}$

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