Which of the following is not true?

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If $E^{\circ} (M^{n +} ∣ M)$ is positive, $M^{n +}$ can be reduced to M by $H_{2} (g)$ under standard conditions

If $E^{\circ} (M^{n +} ∣ M)$ is negative, $H^{+}$ will be reduced to $H_{2}$ by the metal Munder standard conditions

The compounds of active metals such as Zn, Na and Mg are reducible by $H_{2}$ under standard conditions while those of noble metals such as Cu, Ag and Au are not reducible by $H_{2}$ .

Sign of electrode potential determines the nature of the electrode (whether positive or negative terminal) of a cell whose other electrode is standard hydrogen electrode and the cell has a positive emf

answer is C.

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Detailed Solution

The reduction potentials of ${Zn}^{2 +}, {Na}^{+}$ and ${Mg}^{2 +}$ are negative whereas those of ${Cu}^{2 +}, {Ag}^{+}$ and ${Au}^{3 +}$ are positive. Thus, ${Cu}^{2 +}, {Ag}^{+}$ and ${Au}^{3 +}$ are reducible with $H_{2} (g)$ whereas ${Zn}^{2 +}, {Na}^{+}$ and ${Mg}^{2 +}$ are not reducible.