Which of the following is Sandmeyer reaction?

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$2 C_{6} H_{5} Cl \overset{{Cu}_{2} {Cl}_{2} / HCl}{⟶} C_{6} H_{6} + {Cl}_{2}$

$C_{6} H_{5} N_{2} Cl \underset{{Cu}_{2} {Cl}_{2} / HCl}{⟶} C_{6} H_{5} Cl + N_{2}$

$C_{6} H_{5} {NO}_{2} + 6 [H] \overset{Sn / HCl}{⟶} C_{6} H_{5} {NH}_{2} + 2 H_{2} O$

$C_{6} H_{5} OH \overset{Zn dust}{⟶} C_{6} H_{6} + ZnO$

answer is B.

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Detailed Solution

Sandmeyer reaction is

$C_{6} H_{5} N_{2} Cl \overset{{Cu}_{2} {Cl}_{2} / HCl}{⟶} C_{6} H_{5} Cl + N_{2}$

An arene diazonium salt combines with cupric chloride in hydrochloric acid in Sandmeyer's reaction to produce chlorobenzene.

So option B is the correct Answer.

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