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Q.

Which of the following is the correct order of bond length in ${SF}_{3} Cl$ ?
( $a$ is axial and e is equatorial)

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a

$S - F_{a} > S - F_{e} > S - Cl$

b

$S - F_{e} > S - Cl > S - F_{a}$

c

$S - Cl > S - F_{a} > S - F_{e}$

d

$S - F_{a} > S - Cl > S - F_{e}$

answer is D.

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Detailed Solution

Question Image

$(S - Cl) > (S - F)_{a} > (S - F)_{e}$

Hence, the correct answer is $S - Cl > S - F_{a} > S - F_{e}$ .

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