AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Which of the following is the force of gravitation between you (mass: $50 kg$ ) and your friend (mass: $60 kg$ ) sitting $1 m$ away from you?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

20.01 \times 10^{- 8} N

20.01 \times 10^{8} N

200.1 \times 10^{- 8} N

200.1 \times 10^{8} N

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The gravitation between me (mass:

50 kg

) and my friend (mass:

60 kg

) sitting

1 m

away from me is

20.01 \times 10^{- 8} N

.
As per Newton’s law of gravitation we know that

F = \frac{G m_{1} m_{2}}{r^{2}} - - - - - - (a)

where

G

is the gravitational constant (

6.67 \times 10^{- 11} N m^{2} {kg}^{- 2}

)

m_{1}

is the mass of the 1st object

m_{2}

is the mass of the 2nd object

r

is the distance between them
Here we are asked to find the gravitational force between two bodies. We are available with the values to find the gravitational force between

m_{1}

and

m_{2}

which is

50 kg

and

60 kg

respectively.
Distance between two bodies,

r = 1 m

.
Substituting these values in the equation (a)
we can write

F = \frac{6.67 \times 10^{- 11} \times 50 \times 60}{1^{2}}

\Rightarrow F = 6.67 \times 3 \times 10^{- 8} N

\Rightarrow F = 20.01 \times 10^{- 8} N

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!