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Q.

Which of the following is the sides of the polygon whose interior angle exceeds by 108 0   of the exterior angle?


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a

16

b

14

c

12

d

10 

answer is D.

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Detailed Solution

Given,
The interior angle of a regular polygon exceeds its exterior angle by 108 0  .
We know that,
Interior angle of a n-sided polygon = 180 0 360 n 0   Exterior angle of a n-sided polygon 360 n 0   Hence,
180 0 360 n 0 108 0 = 360 0 n 72 0 = 360 0 n + 360 0 n 72 0 = 720 0 n n= 720 0 72 0 n=10  
Hence, the number of sides of the given polygon is n = 10.
Therefore, option 4 is correct.
 
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