Which of the following is true about the complex $\left[{\mathrm{PtCl}}_2\left({\mathrm{NH}}_3\right){\mathrm{OH}}_2\right]$? (Atomic number of Pt = 78]

(P) It will have two geometrical isomeric forms, cis and trans

(Q) The hybridization state of Pt(II) is ${\mathrm{sp}}^2$

(R) It is a square planar complex.

(S) It is a diamagnetic complex 

(T) It can show hydrate isomerism 

(U) It is tetrahedral complex

Geometrical isomerism exists in the complex $\left[{\mathrm{PtCl}}_2\left({\mathrm{NH}}_3\right){\mathrm{OH}}_2\right]$ in the form of cis and trans isomers.

Platinum has an oxidation state of +2 and an outer electronic configuration of $5{\mathrm{d}}^8$. 

Pt is ${\mathrm{dsp}}^2$ hybridised, resulting in square planar geometry.

All of the electrons are paired, and the molecule is diamagnetic.

So, option A is correct answer.