Which of the following is true for $O_{2}$ and $C_{2}$ molecules according to M.O.T.?

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Both are having $1 σ$ and $1 π$ bond

Both have same bond length

Both are having two $π$ bonds

Both are having same bond order

answer is C.

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Detailed Solution

Since oxygen contains 8 electrons. Consequently, $O_{2}$ 's electronegative configuration

the result of having 16 electrons

$σ_{1 s}^{2} σ_{1 s}^{* 2} σ_{2 s}^{2} σ_{2 s}^{* 2} σ_{2 pz}^{2} π_{2 py}^{2} = π_{2 pr}^{2} π_{2 py}^{* 1} = π_{2 p}^{*}$

Bond order :- $\frac{|N_{a} - N_{b}|}{2} = \frac{| 6 - 10 |}{2} = 2$

$O_{2}$ has a bond order of 2.

Given that carbon contains six electrons, the electrical configuration of carbon with twelve electrons is

$σ_{1 s}^{2} σ_{1 s}^{* 2} σ_{2 s}^{2} σ_{2 s}^{*} π_{2 p y}^{2} = π_{2 p}^{2}$

Bond order:- $\frac{| 4 - 8 |}{2} = 2$

So, the bond order of $C_{2}$ is 2 .

$C_{2}$ and $O_{2}$ have same B.O = 2.0 but $C_{2}$ has $2 π$ bonds while $O_{2}$ has 10 and $1 π$ .

Hence correct option is C.

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