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Which of the following is/are correct for ${OF}_{2}, O_{2} F_{2}$ and $H_{2} O_{2}$ ?

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$d_{O - 0} (O - O$ bond length) is less in $O_{2} F_{2}$ than that in $H_{2} O_{2}$

$∠ F O F in {OF}_{2}$ is less than $∠ F O F in {OF}_{2}$

$∠ F O F in {OF}_{2}$ is more than $∠ F O F in {OF}_{2}$

${OF}_{2}$ is an odd electron species.

answer is A, B.

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Detailed Solution

Because of partial double bond character in $O - O$ bond.

The correct for ${OF}_{2}, O_{2} F_{2}$ and $H_{2} O_{2}$ is, $∠ F O F in {OF}_{2}$ is less than $∠ F O F in {OF}_{2}$ and $d_{O - 0} (O - O$ bond length) is less in $O_{2} F_{2}$ than that in $H_{2} O_{2}$ .

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