Questions

Which of the following is/are correctly matched?

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[Co {({PMe}_{3})}_{4}] - s p^{3}

and one unpaired electron.

[Ni (en)_{3}] {({NO}_{2})}_{2} - {sp}^{3} d^{2}

and two unpaired electrons.

[V {({NH}_{3})}_{6}] {Cl}_{3} - s p^{3} d^{2}

and two unpaired electrons.

[Mn {({NO}^{+})}_{3} (CO)] - s p^{3}

and diamagnetic.

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detailed solution

Correct option is A

The hybridization of $[Co {({PMe}_{3})}_{4}] - s p^{3}$ is and in this, the unpaired electron is 1.

The hybridization of $[Ni (en)_{3}] {({NO}_{2})}_{2} - {sp}^{3} d^{2}$ is and in this, the unpaired electron is 2.

The hybridization of $[Mn {({NO}^{+})}_{3} (CO)] - s p^{3}$ is and in this, the unpaired electron 1 and diamagnetic.

Hence, the correct option is a, b and d.

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