Which of the following is/are correctly matched?

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$[V {({NH}_{3})}_{6}] {Cl}_{3} - s p^{3} d^{2}$ and two unpaired electrons.

$[Co {({PMe}_{3})}_{4}] - s p^{3}$ and one unpaired electron.

$[Ni (en)_{3}] {({NO}_{2})}_{2} - {sp}^{3} d^{2}$ and two unpaired electrons.

$[Mn {({NO}^{+})}_{3} (CO)] - s p^{3}$ and diamagnetic.

answer is A, B, D.

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Detailed Solution

The hybridization of $[Co {({PMe}_{3})}_{4}] - s p^{3}$ is and in this, the unpaired electron is 1.

The hybridization of $[Ni (en)_{3}] {({NO}_{2})}_{2} - {sp}^{3} d^{2}$ is and in this, the unpaired electron is 2.

The hybridization of $[Mn {({NO}^{+})}_{3} (CO)] - s p^{3}$ is and in this, the unpaired electron 1 and diamagnetic.

Hence, the correct option is a, b and d.

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