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Which of the following lanthanoid ions is diamagnetic? (At. nos. Ce = 58, Sm = 62, Eu = 63, Yb = 70)

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${Ce}^{2 +}$

${Eu}^{2 +}$

${Yb}^{2 +}$

${Sm}^{2 +}$

answer is D.

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Detailed Solution

• Lanthanide ion with no unpaired electron is diamagnetic in nature.

Ion	z	EC	No. of un-paired e-	Magnetic nature
${Yb}^{+ 2}$	70	$[Xe] f^{14}$	0	d*
${Ce}^{+ 2}$	58	$[Xe] 4 f^{2}$	2	p*
${Sm}^{2 +}$	62	$[Xe] 4 f^{6}$	6	p*
${En}^{+ 2}$	63	$[Xe] 4 f^{7}$	7	p*

* p = paramagnetic
* d = diamagnetic

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