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Which of the following ‘lanthanoid ions’ is diamagnetic
(At. no. Ce = 58, Sm = 62, Eu = 63, Yb = 70)

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${Yb}^{2 +}$

${Ce}^{2 +}$

${Sm}^{2 +}$

${Eu}^{2 +}$

answer is A.

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Detailed Solution

Lanthanide ion with no unpaired electron is diamagnetic in nature.
Ce₅₈ = 4f²5d⁰6s²
Ce²⁺= [xe] 4f²
Sm₆₂= 4f⁶5d⁰6s²
Sm⁺= [xe] 4f⁶
Eu₆₃= [xe] 4f⁷5d⁰6s²
Eu⁺= [xe] 4f⁷(seven unpaired electrons)
Yb₇₀ = [xe] 4f¹⁴5d⁰6s²
Yb⁺= [xe] 4f¹⁴(No unpaired electrons)
Hence Yb⁺ is diamagnetic, due to the absence of the unpaired electron.

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