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Q.

Which of the following ‘lanthanoid ions’ is diamagnetic

(At. no. Ce = 58, Sm = 62, Eu = 63, Yb = 70)

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a

Yb2+

b

Ce2+

c

Sm2+

d

Eu2+

answer is A.

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Detailed Solution

  • Lanthanide ion with no unpaired electron is diamagnetic in nature.
  • Ce58​   = 4f2 5d0 6s2
  • Ce2+ = [xe] 4f2
  • Sm62 ​= 4f6 5d0 6s2
  • Sm+ = [xe] 4f6
  • Eu63 ​= [xe] 4f7 5d0 6s2
  • Eu+ = [xe] 4f7(seven unpaired electrons)
  • Yb70​ = [xe] 4f14 5d0 6s2
  • Yb+ = [xe] 4f14(No unpaired electrons)
  • Hence  Yb+ is diamagnetic, due to the absence of the unpaired electron.
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