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Q.

Which of the following octahedral complex does not show geometrical isomerism (A and B are monodentate ligands)

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a

[MA3B3]

b

[MA4B2]

c

[MA5B]

d

[MA2B4]

answer is C.

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Detailed Solution

  • This type of isomerism is found in heteroleptic complexes due to different possible geometrical arrangements of the ligands.
  •  When two identical groups occupy adjacent positions, the isomer is called cis and when arranged opposite to one another, the isomer is called trans.
  • [MA5B] is the octahedral complex that will not show geometrical isomerism because it is symmetric.
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