Which of the following option is correct about ${\mathrm{NO}}_2$ & ${\mathrm{ClO}}_2$ ?

$\left(i\right)$ Both are paramagnetic species    

$\left(ii\right)$ Both compounds dimerized readily

$\left(iii\right)$ Both have ${\mathrm{sp}}^2$ hybridization       

$\left(iv\right)$ Both have Bent shape.

The total number of electrons in NO₂ is 23 and in ClO₂ is 33. As both have an odd number of electrons, thereby they have unpaired electrons and show paramagnetic behavior.

There is an odd electron in NO₂, therefore it is combined with another molecule of NO₂ and forms a dimer, N₂O₄. There is one odd electron in ClO₂ but due to having vacant orbitals of Cl, this odd electron delocalize in these vacant orbitals and is not available for dimerization.

Hybridization of N in NO₂ is sp² and hybridization of Cl in ClO₂ is also sp². They suppose to have a trigonal planar structure, but due to having lone pair of electrons and an odd electron, they have a bent shape.