Which of the following option is correct for the structure of ${\mathrm{P}}_4{\mathrm{O}}_{10}$ ? 

(a) $6 \mathrm{P}–\mathrm{O}–\mathrm{P}$ linkages        (b) $4 \mathrm{P}=\mathrm{O}$ Bonds 

(c) There are 12 sigma bonds   (d) 4 P atoms are ${\mathrm{sp}}^3$ hybridized.

Phosphorus pentoxide has a formula, P₄O₁₀. The structure of P₄O₁₀ is shown below:

In P₄O₁₀, there are 6 P-O-P linkages and four P=O bonds. The hybridization of P in P₄O₁₀ is sp³. There are 16 sigma bonds in P₄O₁₀.