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Which of the following option is correct regarding $[Fe {(H_{2} O)}_{5} {NO] SO}_{4}$ ?
(P) Fe in+ 2 oxidation state
(Q) It obey's Sidgwick EAN rule
(R) It is an outer orbital complex
(S) NO ligand has +1 oxidation state.

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answer is A.

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Detailed Solution

It is an outer orbital complex and NO ligand has +1 oxidation state is correct regarding

$\begin{array}{l} [Fe {(H_{2} O)}_{5} {NO}_{i}] {SO}_{4} \\ {[Fe {(H_{2} O)}_{5} {NO}^{+ 1}]}_{{SO}_{4}}^{- 2} \\ EAN = 26 - 1 + 12 = 37 \end{array}$

$s p^{3} d^{2}$ hybridization.

Hence, option D is correct.

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