Which of the following option will be the limiting molar conductivity of CH₃COOH if the limiting molar conductivity of CH₃COONa is $91{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}?$ Limiting molar conductivity for individual ions are given in the following table.

S.No	Ions	limiting molar  conductivity / ${\mathrm{Scm}}^2{\mathrm{mol}}^{-1}$
1	${\mathrm{H}}^{+}$	349.6
2	${\mathrm{Na}}^{+}$	50.1
3	${\mathrm{K}}^{+}$	73.5
4	OH	199.1

The limiting molar conductivity $\left({\wedge }_{\mathrm{m}}^{\mathrm{o}}\right)$  for strong and weak electrolyte can be determined by using Kohlrausch's law which states that "the limiting molar conductivity of an electrolyte can be represented as the sum of the individual contributions of the anion and cation of the electrolyte."

${\wedge }_{{\mathrm{CH}}_3\mathrm{COONa}}={\wedge }_{{\mathrm{CH}}_3{\mathrm{COO}}^{-}}+ {\wedge }_{{\mathrm{Na}}^{+}}$

$91{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}{=}^{\wedge }{\mathrm{CH}}_3{\mathrm{COO}}^{-}+50.1{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}$

$\Rightarrow {\wedge }_{{\mathrm{CH}}_3{\mathrm{COO}}^{-}}=40.9{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}$

For acetic acid,

$$\begin{gathered} \begin{array}{l}{\wedge }_{{\mathrm{CH}}_3\mathrm{COOH}}={\wedge }_{{\mathrm{CH}}_3{\mathrm{COO}}^{-}}+{\wedge }_{{\mathrm{H}}^{+}}\\ =40.9{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}+349.6{\mathrm{Scm}}^2{\mathrm{mol}}^{-1}\end{array} \\ =390.5{\mathrm{Scm}}^2{\mathrm{mol}}^{-1} \end{gathered}$$