Which of the following options are correct for ${[Fe (CN)_{6}]}^{3 -}$ complex?

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diamagnetic

paramagnetic

$s p^{3} d^{2}$ hybridisation

$d^{2} s p^{3}$ hybridisation

answer is A, C.

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Detailed Solution

${[Fe (CN)_{6}]}^{3 -}$ complex is $d^{2} s p^{3}$ hybridisation and paramagnetic.

Presence of one unpaired electron in 3d shell ${[Fe (CN)_{6}]}^{3 -}$ ion is paramagnetic in nature. Shape of ${[Fe (CN)_{6}]}^{3 -}$ is $d^{2} s p^{3}$ and octahedral. Hence, options A and C are correct.

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