Which of the following options are correct regarding the $X e O_{3} F_{2}$ and $X e O F_{4}$ molecules?

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$d_{Xe - O ({XeO}_{3} F_{2})} < d_{Xe - O ({XeOF}_{4})}$

$d_{Xe - F ({XeO}_{3} F_{2})} < d_{Xe - F ({XeOF}_{4})}$

Shapes are trigonal bipyramidal and square pyramidal respectively

The nature of rt-bond is of $5 d_{π} - 2 p_{π}$ type

answer is A, C, D.

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Detailed Solution

$X e O_{3} F_{2} a n d X e O F_{4}$ Its trigonal bipyramidal structure places the fluoride atoms on top and bottom and the oxygen atoms on the plane.

The nature of $π$ -bond is of $5 d_{π} - 2 p_{π}$ type. and the structure have of both $X e O_{3} F_{2} a n d X e O F_{4}$ is

$d_{Xe - O ({XeO}_{3} F_{2})} < d_{Xe - O ({XeOF}_{4})}$

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