Which of the following options are correct regarding the $Xe{O}_3{F}_2$ and $XeO{F}_4$ molecules?

$Xe{O}_3{F}_2\mathit{ }and\mathit{ }XeO{F}_{\mathit{4}}$ Its trigonal bipyramidal structure places the fluoride atoms on top and bottom and the oxygen atoms on the plane.

The nature of $\mathrm{\pi }$-bond is of $5d_{\pi }-2p_{\pi }$ type. and the structure have of both $Xe{O}_3{F}_2\mathit{ }and\mathit{ }XeO{F}_{\mathit{4}}$ is

$d_{\mathrm{Xe}-\mathrm{O}\left({\mathrm{XeO}}_3{\mathrm{F}}_2\right)}<d_{\mathrm{Xe}-\mathrm{O}\left({\mathrm{XeOF}}_4\right)}$