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Q.

Which of the following options represent correct composition of a gaseous mixture containing ${CH}_{4} (g)$ and $N_{2} O_{5} (g)$ and having vapour densty equal to 19.5?

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a

Mass% of ${CH}_{4} = 25 %$

b

Mole% of ${CH}_{4} = 25 %$

c

Mass% of ${CH}_{4} = 75 %$

d

Mole% of ${CH}_{4} = 75 %$

answer is D.

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Detailed Solution

$\begin{aligned} M_{a v g} = \frac{x \times M_{C_{H_{0}}} + (100 - x) \times M_{N_{2} 0_{1}}}{100} \\ (2 \times 19.5) \times 100 = 16 x + 108 (100 - x) \\ 3900 = 16 x + 10800 - 108 x \\ \Rightarrow 92 x = 6900 \Rightarrow x = 75 \\ \Rightarrow The mole percentage = 75 % \end{aligned}$

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