Which of the following order is/ are incorrect for bond angle?

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${NH}_{3} < {PH}_{3} < {AsH}_{3} < {SbH}_{3}$

${OF}_{2} < {OCl}_{2} < {OBr}_{2} > H_{2} O$

${BF}_{3} < {BCl}_{3} < {BBr}_{3} < {BI}_{3}$

${NO}_{2}^{+} > {NO}_{2}^{-} < {NO}_{3}^{-}$

answer is A, C.

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Detailed Solution

As we move down the group, radius of elements increases and electronegativity decreases so bond angle decreases.

The order of bond angle of halides of boron is ${Bi}_{3} > {BBr}_{3} > {BCl}_{3} > {BF}_{3}$ . Effective overlap between orbitals decreases due to the large size of the p orbital of halides.

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