Which of the following order is correct?

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Solubility order: ${BeF}_{2} < {MgF}_{2} < {CaF}_{2} < {SrF}_{2} < {BaF}_{2}$

Acidic order $: {({CH}_{3})}_{3} C - OH > {({CH}_{3})}_{3} Si - OH$

Stability order : $N_{2}^{+} < N_{2}^{-}$

Rate of hydrolysis : ${SF}_{4} > {SF}_{6}$

answer is D.

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Detailed Solution

Order Rate of hydrolysis: ${SF}_{4} > {SF}_{6}$

As, the S-atom in the ${SF}_{6}$ molecule is still surrounded by six F-atoms. As a result of this steric barrier, $H_{2} O$ is unable to attack the S-atom. Because the F atom lacks a d-orbital to take an unshared electron pair from $H_{2} O$ , the S atom in ${SF}_{6}$ is coordinatively saturated. As a result, hydrolysis does not occur in ${SF}_{6}$ . In contrast, just four F-atoms surround the S-atom in SF4, which means that the assault by water is not sterically inhibited. S-atom is not coordinately saturated in ${SF}_{4}$ . So ${SF}_{4}$ readily passes through hydrolysis.