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Which of the following order is correct?

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$Xe < He$ (Solubility in water

$I_{3}^{-} < {Cl}_{3}^{-}$ (Stability

$H_{2} O (0^{\circ} C) < H_{2} O (4^{\circ} C)$ (Volume of same mass)

${CH}_{4} < C_{2} H_{6}$ (Boiling point)

answer is D.

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Detailed Solution

Which hydrocarbon has a greater boiling point ${CH}_{4}$ or $C_{2} H_{6} . {CH}_{4}$ has a molar mass of 16.0426 grammars. Due to its larger molar mass and hence stronger dispersion forces, $C_{2} H_{6}$ has a higher boiling point.

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