Which of the following order is correct for covalent character (if the cation sizes are identical in pairs)?

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All of these

${CaCl}_{2} < {PdCl}_{2}$

$\begin{array}{l} NaCl < CuCl \end{array}$

$Rb < l < Cl$

answer is D.

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Detailed Solution

left to right in period covalent character increasing and top to down in group ionic character decreasing.
Hence the result,
$\begin{array}{l} {CaCl}_{2} < {PdCl}_{2} \\ NaCl < CuCl \\ RbCl < AuCl \end{array}$
Hence, correct option is D.

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