Which of the following order is correct for the indicated property?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$I_{2} > {Br}_{2} > {Cl}_{2} > F_{2} (Reactivity)$

$Li (a q_{.}) > Na (a q_{.}) > K^{+} (a q_{\cdot}) (electrical conductivity)$

$Na > Mg > Cu (Electropositive character)$

$N^{- 3} > O^{- 2} > {Mg}^{+ 2} > {Na}^{+} (Ionic size)$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

For the electropositive charracter , the correct order is $Na > Mg > Cu$

Sodium lose electrons relatively quickly due to low ionization energy. As a result, they can be described as strongly electropositive. As we descend the group from Cu to Na, the electropositive property gets stronger.

They let off electrons when exposed to light because they have a strong electropositive character. The phrase “photo-electric effect” is used to describe this phenomenon. Photoelectric cells extensively utilize these components.

Sodium is employed much more in photoelectric cells than other alkali metals, since it is extremely electropositive compared to other elements.

Hence, the correct order is: $Na > Mg > Cu (Electropositive character)$

Watch 3-min video & get full concept clarity