Which of the following order of energies of molecular orbitals of $N_{2}$ is correct?

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$E (π 2 p_{x}) = E (π 2 p_{y}) < E (σ 2 p) < E (π^{*} 2 p_{x}) = E (π^{*} 2 p_{y})$

$E (π 2 p_{x}) = E (π 2 p_{y}) > E (σ 2 p) > E (π * 2 p_{x}) = E (π^{*} 2 p_{y})$

$E (π 2 p_{x}) = E (π 2 p_{y}) < E (σ 2 p) > E (π^{*} 2 p_{x}) = E (π^{*} 2 p_{y})$

$E (π 2 p_{x}) = E (π 2 p_{y}) > E (σ 2 p) < E (π^{*} 2 p_{x}) = E (π^{*} 2 p_{y})$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Molecules like B2,C2 & N2 having 1 to 3 electrons in p orbital energy of σ2p molecular orbital is greater than that of π2px and π2py molecular orbitals.

Watch 3-min video & get full concept clarity

hear from our champions

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!