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Which of the following order represents the incorrect order for the properties indicated against them?

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$H_{2} S < H_{2} S e < H_{2} T e$ (acidic character)

$H_{2} S > H_{2} S e > H_{2} T e$ (Reducing nature)

$H_{2} S > H_{2} S_{2} > H_{2} T e$ (thermal stability)

$H_{2} S < H_{2} S e < H_{2} T e$ (covalent character)

answer is B.

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Detailed Solution

As the thermal stability decreases, the reducing character increases
Melting point: $H_{2} O (373) > H_{2} T e (222) > H_{2} S e (208) > H_{2} S (188) K .$
Reducing nature: $H_{2} S < H_{2} S e < H_{2} T e$

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