Which of the following orders of melting points of hydrides of Group 16 elements is true?

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$H_{2} S < H_{2} Se < H_{2} Te$

$H_{2} S > H_{2} Se > H_{2} Te$

$H_{2} S > H_{2} Se < H_{2} Te$

$H_{2} S < H_{2} Se > H_{2} Te$

answer is B.

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Detailed Solution

Here, the covalent hydrides,
Melting point is proportional to Van der waal′s force which is again proportional to the Molecular mass
So, the melting point order can be given as,

$H_{2} Te > H_{2} Se > H_{2} S$

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