Which of the following pair of acid radicals can be distinguished by using dil. $H_{2} S O_{4}$ ?

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$N O_{3}^{Θ} a n d N O_{2}^{Θ}$

$C_{2} {O_{4}}^{2 -} a n d N {O_{3}}^{Θ}$

$H C O_{3}^{-} a n d C O_{3}^{^{- 2}}$

$C l^{Θ} a n d B r^{Θ}$

answer is B.

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Detailed Solution

(1) ${\begin{cases} \to C_{2} {O_{4}}^{2 -} + 2 H^{\oplus} \overset{d i l . H_{2} S O_{4}}{\to} N O v a p o u r s \\ o r g a s i s e v o l v e d \\ \to N {O_{3}}^{Θ} : n o r e a c t i o n w i t h d i l . H_{2} S O_{4} \end{cases}$
(2) $\begin{array}{l} {\begin{cases} \to N {O_{3}}^{Θ} : N o r e a c t i o n w i t h d i l . H_{2} S O \\ \to N {O_{2}}^{Θ} + H^{\oplus} \overset{d i l . H_{2} S O_{4}}{\to} H N O_{2} \end{cases} \\ D i s p r o p o r t i o n a t i o n ↓ \\ N O_{2} ↑ \overset{A t m . a i r}{\leftarrow} H N O_{3} + N O ↑ \\ L i g h t b r o w n \end{array}$
Hence, distinction is possible
(3) Both $C l^{Θ} a n d B r^{Θ}$ have no reaction with dil. $H_{2} S O_{4}$ .
(4) Both $H C {O_{3}}^{Θ} a n d C {O_{3}}^{2 -} p r o d u c e C O_{2} ↑$ which evolves with
effervescence