Which of the following pairs has/have the same number of atoms?

$\text{ (c) Number of atoms in }28 \mathrm{g}\text{ of }$

${\mathrm{N}}_2=\frac{28}{28}\times {\mathrm{N}}_{\mathrm{A}}\times 2=2{\mathrm{N}}_{\mathrm{A}}$

$\text{ (where, }{\mathrm{N}}_{\mathrm{A}}=\text{ Avogadro number) }$

$\text{ Number of atoms in }32 \mathrm{g}\text{ of }{\mathrm{O}}_2=\frac{32}{32}\times {\mathrm{N}}_{\mathrm{A}}\times 2=2{\mathrm{N}}_{\mathrm{A}}$

$\text{ (d) }12 \mathrm{g}\text{ of }\mathrm{C}\left(\mathrm{s}\right)\text{ contains atoms }=\frac{12}{12}\times {\mathrm{N}}_{\mathrm{A}}\times 1={\mathrm{N}}_{\mathrm{A}}$

$\text{ Number of atoms in }23 \mathrm{g}\text{ of }\mathrm{Na}\left(\mathrm{s}\right)=\frac{23}{23}\times {\mathrm{N}}_{\mathrm{A}}\times 1={\mathrm{N}}_{\mathrm{A}}$