Q.

Which of the following pairs of species has identical value of bond order?

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a

N2 and O2+

b

CO and N2+

c

NO+, N2

d

CN, O2+

answer is A.

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Detailed Solution

Valence electrons of N2=10 Electronic Configuration (σ2s)2(σ2s)2π2px2π2py2σ2pz2

Bond order =(82)/2=3

Valence electrons of NO+=10  (σ2s)2(σ2s)2π2px2π2py2σ2pz2

Bond order =(82)/2=3

Valence electrons of CO=10; Same as NO+

Valence electrons of CN=10; Same as NO+

Valence electrons of N2=11 Bond order =(92)/2=3.5

Valence electrons of O2+=11Electronic configuration (σ2s)2(σ2s)2σ2pz2π2px2π2py2π2px1

Bond order =(83)/2=2.5

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