Which of the following paramagnetic species has the highest bond order

${\mathrm{N}}_2$ & ${\mathrm{C}}_2^{-2}$ (14 electrons) - diamagnetic

${\mathrm{O}}_2^{+}$ (paramagnetic)- $\mathrm{KK\sigma }2{\mathrm{s}}^2{\mathrm{\sigma }}^{*}2{\mathrm{s}}^2\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{x}}^2(\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}^2=\mathrm{\pi }2{\mathrm{p}}_{\mathrm{z}}^2)({\mathrm{\pi }}^{*}2{\mathrm{p}}_{\mathrm{y}}^1={\mathrm{\pi }}^{*}2{\mathrm{p}}_{\mathrm{z}}^0)$

          $Bond order =\frac{n_b-n_a}{2}=\frac{10-5}{2}=2.5$

${\mathrm{O}}_2^{-}$(paramagnetic)- $\mathrm{KK\sigma }2{\mathrm{s}}^2{\mathrm{\sigma }}^{*}2{\mathrm{s}}^2\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{x}}^2(\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}^2=\mathrm{\pi }2{\mathrm{p}}_{\mathrm{z}}^2)({\mathrm{\pi }}^{*}2{\mathrm{p}}_{\mathrm{y}}^2={\mathrm{\pi }}^{*}2{\mathrm{p}}_{\mathrm{z}}^1)$

                                 $Bond order =\frac{n_b-n_a}{2}=\frac{10-7}{2}=1.5$