AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Which of the following property of $Pb$ is due to the consequence of inert pair effect?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

Higher stability of ${Pb}^{4 +}$ as compared to ${Pb}^{2 +}$

Higher stability of ${Pb}^{2 +}$ as compared to ${Sn}^{2 +}$

Size of ${Pb}^{2 +}$ is 133 but size of ${Pb}^{4 +}$ is 84

${Pb}^{4 +}$ has oxidising property

answer is B, D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Pb⁴⁺ can easily lose 2 electrons to produce Pb²⁺ and thus Pb⁴⁺ acts as an oxidising agent.

According to inert pair effect, ${Pb}^{2 +}$ 2 is more stable than ${Sn}^{2 +}$ .

As the relative property to be in higher oxidation state of elements of same group, increases down the group.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!