Which of the following reaction(s) can be used for the preparation of alkyl halides?

$\text{ (I) }{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}+\mathrm{HCl}\stackrel{\text{ anh. }{\mathrm{ZnCl}}_2}{⟶}$

$\text{ (II) }{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}+\mathrm{HCl}⟶$

$\left(\mathrm{III}\right){\left({\mathrm{CH}}_3\right)}_3\mathrm{COH}+\mathrm{HCl}⟶$

$\left(\mathrm{IV}\right){\left({\mathrm{CH}}_3\right)}_2\mathrm{CHOH}+\mathrm{HCl}\stackrel{\text{ anh. }{\mathrm{ZnCl}}_2}{⟶}$

The reactions (I),(III) and (IV) only can be used for the preparation of alkyl halides.
Alkyl halide is prepared by the reaction of an alcohol with HCl in which -OH group is replaced with Cl.
Primary and secondary alcohols requires catalyst such as anhydrous zinc chloride.
Tertiary alcohols do not require such catalyst as they are more reactive.