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Q.

Which of the following reactions will not form acetal aldehyde?

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a

${CH}_{3} {CH}_{2} OH \to_{H 2 {SO}_{4}}^{{CrO}_{3}}$

b

${CH}_{2} = {CH}_{2} \overset{pd (II), Cu (II) H_{2} O}{\to}$

c

${CH}_{3} CN \to_{H_{2} O}^{DiBAl - H}$

d

${CH}_{3} {CH}_{2} OH \to_{573 K}^{Cu}$

answer is B.

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Detailed Solution

${CH}_{3} {CH}_{2} OH \to_{H 2 {SO}_{4}}^{{CrO}_{3}} {CH}_{3} COOH$

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