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Q.

Which of the following reagents convert propene to 1-propanol?

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a

$H_{2} O, H_{2} {SO}_{4}$

b

Aqueous KOH

c

${MgSO}_{4}, {NaBH}_{4} / H_{2} O$

d

$B_{2} H_{6}, H_{2} O_{2}, {OH}^{-}$

answer is D.

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Detailed Solution

$\underset{1, Propene}{6 {CH}_{3} - CH = {CH}_{2}} \underset{ether, 0 ° c}{\overset{B_{2} H_{6}}{\to}} 2 {({CH}_{3} {CH}_{2} {CH}_{2})}_{3} B \underset{{OH}^{-}}{\overset{H_{2} O_{2}}{\to}} 6 \underset{propanol}{{CH}_{3} {CH}_{2} {CH}_{2} OH} + 2 H_{3} {BO}_{3}$

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