Which of the following represents the correct order of increasing first ionization enthalpy for $C a, B a, S, S e, A r ?$

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$Ba < Ca < Se < S < Ar$

$Ca < Ba < S < Se < Ar$

$Ca < S < Ba < Se < Ar$

$S < Se < Ca < Ba < Ar$

answer is A.

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Detailed Solution

Ba, Ca belongs to group IIA (alkaline earth metals) Se,S belongs to group VIA (halogens) and as we go down the group ionization enthalpy decreases with increasing atomic size so, $B a < C a$ and $S e < S$

Ar has stable completely filled electronic configuration and therefore has highest ionization enthalpy. Hence the correct order is

$\begin{array}{l} B a < C a < S e < S < A r \\ i n K J / m o l e 503 590 941 999 1520 \end{array}$

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