Which of the following set is incorrect ?

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Ni(CO)₄ – Tetrahedral, paramagnetic

[Ni(CN)₄]^2– – Square planar, diamagnetic

Ni(CO)₄– Tetrahedral, diamagnetic

[NiCl₄]^2– – Tetrahedral, paramagnetic

answer is A.

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Detailed Solution

Nickel oxidation state in Ni(CO)₄ is 0 and its outer electronic configuration becomes 3d⁸ 4s². When CO (strong ligand) approaches Ni, pairing of electrons takes place. This results in the formation of a tetrahedral complex and it is diamagnetic as there is no unpaired electrons.

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