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Q.

Which of the following set is incorrect ?

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a

Ni(CO)4– Tetrahedral, diamagnetic

b

[NiCl4]2– – Tetrahedral, paramagnetic

c

[Ni(CN)4]2– – Square planar, diamagnetic

d

Ni(CO)4 – Tetrahedral, paramagnetic

answer is A.

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Detailed Solution

Nickel oxidation state in Ni(CO)4 is 0 and its outer electronic configuration becomes 3d8 4s2. When CO (strong ligand) approaches Ni, pairing of electrons takes place. This results in the formation of a tetrahedral complex and it is diamagnetic as there is no unpaired electrons.

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