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Q.

Which of the following set of orbital results in N.B.M.O ? [If z-axis is the bond formation axis]

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a

px+dyz

b

All of these

c

s+dyz

d

pz+dxz

answer is D.

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Detailed Solution

The signs (symmetry) of the overlapping lobes must match in order to produce a bonding MO (with a concentration of electron density between the nuclei). The signals of the overlapping lobes must also differ for antibonding MOs.

Any stability in the combination above caused by the overlap of + with + is counterbalanced by an equivalent amount of overlap of + with. Nonbonding is the word used to describe a situation when there is no general shift of energy. The same is true for the combination of px and py since they are perpendicular to one another.

Hence, the option D is correct.

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