Which of the following set of orbital results in $N.B.M.O$ ? [If z-axis is the bond formation axis]

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$p_{z} + d_{xz}$

$s + d_{yz}$

$p_{x} + d_{yz}$

All of these

answer is D.

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Detailed Solution

The signs (symmetry) of the overlapping lobes must match in order to produce a bonding MO (with a concentration of electron density between the nuclei). The signals of the overlapping lobes must also differ for antibonding MOs.

Any stability in the combination above caused by the overlap of + with + is counterbalanced by an equivalent amount of overlap of + with. Nonbonding is the word used to describe a situation when there is no general shift of energy. The same is true for the combination of $p_{x}$ and $p_{y}$ since they are perpendicular to one another.

Hence, the option D is correct.

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