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Q.

Which of the following set of quantum own correct for an electron in 4f orbital?

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a

n=4,l=3,m=+4,s=+12

b

n=4,l=4,m=4,s=12

c

n=4,l=3,m=+1,s=+12

d

n=3,l=2,m=2,s=+12

answer is C.

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Detailed Solution

The set of quantum own correct for an electron in 4f orbital n=4,l=3,m=+1,s=+12

The set of quantum numbers for an electron in the 4f orbital is as follows:

The major shell is represented by the principal quantum number n. N = 4 for an electron in the 4f orbital.

The orbitals are represented by the angular momentum quantum number value. which is =+1

The number of electron in S,p,d and f orbitals are 0,1,2 and 3 respectively.

Consequently, l = 3 for an electron in the f orbital.

The range of a magnetic quantum number's possible values ranges from - l to + l.

So, m  = -3, -2, -1, 0, 1, 2, 3.

An electron in a certain orbital will have a spin quantum number of m s = +1/2 or -1/2.
Therefore, ,n = 4,  l  = 3,  m l  = +1,  m s  = +1/2 is the right response.
 

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