Which of the following sets of quantum numbers is correct for an electron in 3d orbital?

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3, 0, 0, $\frac{+ 1}{2}$

3, 2, 1, $\frac{+ 1}{2}$

3, 1, 1, $\frac{- 1}{2}$

3, 2, 3, $\frac{- 1}{2}$

answer is B.

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Detailed Solution

Set of quantum numbers for an electron in 3d orbital is, $n = 3, l = 2, m = 1, s = \frac{+ 1}{2}$ .

For 3d orbital, the principal quantum number, $n = 3$ , for d-orbital $l = 2$ .

For $l = 2$ , m can have values from –l to +l which means from -2 to +2. So possible values of m are -2, -1, 0, +1, +2.

Spin quantum number can have any value of $\frac{+ 1}{2}$ and $\frac{- 1}{2}$ as electrons can have any spin.

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