Which of the following sets of quantum numbers represents the highest energy of an atom

In the given all set of quantum numbers, $\text{n}=3,l=2,\text{\hspace{0.17em}\hspace{0.17em}m}=1,\text{\hspace{0.17em}\hspace{0.17em}s}=+1/2$  has the highest energy of an orbital in an atom. If  $\text{n}=3,l=2$ means it is 3d orbital. Therefore,  $3\text{d}>4\text{s}>3\text{p}>3\text{s}$.