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Which of the following shows the correct decreasing order of acidic character?

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$CH \equiv {CH > CH}_{3} - C - {CH > CH}_{3} - C \equiv C - {CH}_{3}$

${CH}_{3} - C \equiv C - {CH}_{3} > CH \equiv CH > {CH}_{3} - C \equiv CH$

${CH}_{3} - C \equiv CH > CH \equiv {CH > CH}_{3} - C \equiv C - {CH}_{3}$

${CH}_{3} - C \equiv C - {CH}_{3} {> CH}_{3} - C \equiv CH > CH - C \equiv CH$

answer is A.

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Detailed Solution

+I effect of CH₃ group opposes the removal of H-atom of $- C \equiv C - H$ as H⁺ in case of CH₃ – C $\equiv$ C – H.

In case of CH₃ – C $\equiv$ C – CH₃, H-atom of C – H combination is a part of CH₃ where C-atom is sp³-hybridised. The removal of H as H⁺ is very difficult.

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