Which of the following solutions will be definitely basic?

(i) $NaOH + C{H}_{3}COOH \to C{H}_{3}COONa+H_{2}O$
     0.4 × 0.1              0.100 × 0.4
    0.04 mole               0.04 mole                     0                     0
    0                             0   0.04 mole      0.04 mole
Salt of weak acid and strong base formed   basic
(ii)  $M=\frac{W}{V}\%\frac{10}{M_A}=\frac{x\times 10}{40}forNaOH$
     $\begin{array}{l}M\frac{x\times 10}{98}for{H}_{2}S{O}_4\\ n_{f}M{V}_{NaOH}>{\left(n_{f}MV\right)}_{H_{2}SO}\therefore basic\end{array}$
(iii) If volume of NaOH < $\frac{VolumeofHCI}{2}$  then basic 
(iv) 40 gram NaOH means 1 mole NaOH and 40 gram HCI means  $\frac{40}{36.5}>1$ 
 Solution acidic in nature