Which of the following solutions will have pH close to 1.0?

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$100mL of M/10 HCl + 100 mL of M/10 NaOH$

$55 mL of M/10 HCl + 45 mL of M/10 NaOH$

$75 mL of M/5 HCl + 25 mL of M/5 NaOH$

$10 mL of M/10 HCl + 90 mL of M/10 NaOH$

answer is D.

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Detailed Solution

A) $H C l$

No. of milli eq.= $\frac{1}{10} \times 100 = 10$

So Solution is neutral.

$N a O H$

$\frac{1}{10} \times 100 = 10$

B) $\frac{1}{10} \times 55 = 5.5$

$[H^{+}] = \frac{1}{100} = 10^{- 2} M, p H = 2$

\frac{1}{10} \times 45 = 4.5

\frac{1}{10} \times 10 = 1

\frac{1}{10} \times 90 = 9 B a s i c

D) $\frac{1}{5} \times 75 = 15$

$[H^{+}] = 0.1 M, p H = 1$

$\frac{1}{5} \times 25 = 5$

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